JEE-Main 2020: 4 lakh 81 thousand students out of a total of 10 lakh 23 thousand students, gave both exams
A total of 10 lakh 23 thousand students appeared in JEE-Main, the country’s largest engineering entrance examination, which took place in January and September for admission to more than 30 thousand seats of 31 NITs, 23 IIITs and 27 GFTIs. Out of which 4 lakh 81 thousand students are those who took both exams.
Career Counseling Expert of Allen Career Institute said that the result of JEE-Main September was released on Friday, September 11, with the All India Rank of JEE-Main. With this, the cutoff was released in 7 decimals for eligibility to take the JEE-Advanced exam on the basis of JEE-Mains. Top 2 lakh 50 thousand students selected on the basis of JEE-Main have been declared eligible to take the JEE-Advanced exam.
In which cutoff 90.3765335 for 1 lakh 1 thousand 250 students of general category, cutoff 70.2435518 for 25 thousand students of EWS category, cutoff 72.8887969 for 67500 students of OBC NCL category, cutoff 50.1760245 for 37500 students of SC category, the cutoff for the 18750 students of ST was 39.0696101.
This was the difference from last year’s cutoff
ALLEN Career Counselor said that when compared to last year, the cutoff of general category has increased slightly; the cutoff of last year was 89.7548849, while this year was slightly higher. The main reason for this can be considered is that this year 12 thousand 675 students have qualified less for general category. While the cut-off of EWS category has been 7.9739351, the main reason for this can be considered is that 15 thousand 200 students in EWS category have over-qualified. With this, the cutoff of OBC category has been reduced to 1.4278588. 1350 more students are qualified in OBC; similarly, SC and ST cutoff has been reduced to 3.842191 and 5.2649071 respectively. 750 and 375 more students are qualified in SC, ST respectively.
These NITs, IIITs and GFTIs will get from AIR
ALLEN Career Counselor said that the students whose AIR is less than 5 thousand are likely to get the core branches of top NIT Tirchi, Warangal, Suratkal, Allahabad, Jaipur. Students, whose All India rank is between 5 to 10 thousand, are likely to get core branches in NITs like Calicut, Surat, Nagpur, Bhopal, Rourkela in addition to other branches of the top 5 NITs. Students who have AIR between 10 to 20 thousand will be likely to get core branches in Jalandhar, Kurukshetra, Jamshedpur, Delhi, Goa, Agartala, Hamirpur, Durgapur like NIT, IIIT Allahabad, Kota and Bits Misra, Pek Chandigarh.
Students whose All India rank is between 20 to 30 thousand will be likely to get core branches of NITs like Patna, Raipur, Silchar, Uttarakhand, Srinagar, Andhra Pradesh, Arunachal Pradesh in addition to other branches of top 10 NITs, as well as Other branches of TripleIT Gwalior, Jabalpur, Peck Chandigarh, Bits Misra, IIEST Shivpur.
Also, to the students of 30 to 50 thousand All India rank, other than the core branches of the top 20 NITs, as well as new branches, IIITs like Tirchi, Nagpur, Pune, Surat, Bhopal, Vadodara, Lucknow, Ranchi, Guwahati etc. along with this, there will be possibility of getting branches in colleges like GFTI, BITS Misra, JNU, Hyderabad University.
Students whose All India rank is between 50 to 60 thousand, they will get admission in North East NITs like Sikkim, Manipur, Meghalaya, Nagaland, Mizoram as well as other branches of other NITs, new IIIT and GFTI. According to the category of students, there may be some changes in the chances of getting a college branch.
Apply to these colleges as well on the basis of JEE-Main
Students whose ranks are expected to lag behind in JEE-Main need not be disappointed. According to their NTA score and JEE Main All India Rank, a student can apply separately for admission to colleges like DTU, NSIT, IIIT Delhi, Hyderabad, Thapar Patiala. The application process of many of these colleges has started. Therefore, the student can apply for the above colleges by visiting the respective website.
JEE-Advanced 2020 Application Process
ALLEN Expert said that after the release of JEE-Main results, the process of registration of JEE-Advanced started, although the website was hanging all day and students were troubled. For JEE-Advanced exam application, student can login with JEE-Main application number, application number and password created during application.
After login, the student will have to upload the necessary information and documents, in the uploaded documents, the student will have to upload 10th, 12th marks certificate, category certificate. OBC and EWS category certificate is required to be of after April 1, 2020. After this, the required fees can be paid through debit and credit card. The last date for registration is 18 September. The JEE-Advanced exam will be conducted by IIT Delhi on September 27 in 212 cities in two shifts, the result of which will be declared on October 5 at 10 am.